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Continuous random variables: IB Mathematics: Analysis & Approaches questions with answers Free Continuous random variables questions for IB Mathematics: Analysis & Approaches (SL & HL), HL only, part of Statistics & probability. Each question has the answer and the marking points an examiner would look for.
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Continuous random variables practice questions Question 1 Structured · 7 marks
A continuous random variable X has probability density function f(x) = kx2 for 0 ≤ x ≤ 4, and f(x) = 0 otherwise.
Show answers and mark scheme Part Answer and marking points Marks (a) 3 64 k[x3 3 ]0 4 = 1 M1 k = 3 64 A1
2 (b) 3∫0 4 x × 3 64 x2 dx (M1) 3 A1
2 (c) 4 ∛2 ∫0 m 3 64 x2 dx = 1 2 M1 m3 = 64 2 A1 m = 4 ∛2 A1
3
Question 2 Structured · 8 marks
A continuous random variable X has probability density function f(x) = kx(4 − x) for 0 ≤ x ≤ 4, and f(x) = 0 otherwise.
(b) Write down E(X), giving a reason.
[2] Show answers and mark scheme Part Answer and marking points Marks (a) 3 32 ∫0 4 kx(4 − x)dx = 1 M1 k[4x2 2 − x3 3 ]0 4 = 32 3 k A1 k = 3 32 A1
3 (b) 2the pdf is symmetric about x = 2 R1 E(X) = 2 A1
2 (c) 5 32 ∫0 1 3 32 x(4 − x)dx (M1) correct integration and substitution (A1) 5 32 A1
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Question 3 Structured · 7 marks
A continuous random variable X has probability density function f(x) = kx2 for 0 ≤ x ≤ 3, and 0 otherwise.
Show answers and mark scheme Part Answer and marking points Marks (a) 1 9 ∫ f(x) dx = 1 (M1) 1 9 A1
2 (b) 9 4 ∫ x f(x) dx (M1) 9 4 A1
2 (c) 2.38∫ from 0 to m = 0.5 (M1) m3 = 27 2 (A1) 2.38 A1
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Question 4 Structured · 7 marks
A continuous random variable X has probability density function f(x) = kxe−x for 0 ≤ x ≤ 3, and f(x) = 0 otherwise.
Show answers and mark scheme Part Answer and marking points Marks (a) 1.25∫0 3 kxe−x dx = 1 (M1) k = 1.25 A1
2 (b) 1.44∫0 3 x·kxe−x dx (M1) 1.44 A1
2 (c) 1.38∫0 m kxe−x dx = 0.5 (M1) attempt to solve using GDC (M1) m = 1.38 A1
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Question 5 Structured · 8 marks
A continuous random variable X has probability density function f(x) = kx(6 − x) for 0 ≤ x ≤ 6, and f(x) = 0 otherwise.
(b) Write down E(X), giving a reason.
[2] Show answers and mark scheme Part Answer and marking points Marks (a) 1 36 ∫0 6 kx(6 − x)dx = 1 M1 k[6x2 2 − x3 3 ]0 6 = 36k A1 k = 1 36 A1
3 (b) 3the pdf is symmetric about x = 3 R1 E(X) = 3 A1
2 (c) 5 32 ∫0 3/2 1 36 x(6 − x)dx (M1) correct integration and substitution (A1) 5 32 A1
3
Question 6 Structured · 7 marks
A continuous random variable X has probability density function f(x) = kx2 for 0 ≤ x ≤ 2, and 0 otherwise.
Show answers and mark scheme Part Answer and marking points Marks (a) 3 8 ∫ f(x) dx = 1 (M1) 3 8 A1
2 (b) 3 2 ∫ x f(x) dx (M1) 3 2 A1
2 (c) 1.59∫ from 0 to m = 0.5 (M1) m3 = 8 2 (A1) 1.59 A1
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Original IB-style practice questions written for mentorriyaz.in. These are not IB past paper questions, and this site is not affiliated with or endorsed by the International Baccalaureate Organization. Updated 2026-11-04. Paper generator · mentorriyaz.in