IB · Mathematics: Analysis & Approaches SL & HL · Number & algebra

Sequences & series: IB Mathematics: Analysis & Approaches questions with answers

Free Sequences & series questions for IB Mathematics: Analysis & Approaches (SL & HL), part of Number & algebra. Each question has the answer and the marking points an examiner would look for.

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Sequences & series practice questions

Question 1Structured · 6 marksA* challenge

Consider the infinite geometric series 1 + (3x + 45) + (3x + 45)2 + (3x + 45)3 + …

(a)

Find the set of values of x for which the series has a finite sum.

[3]
(b)

The sum to infinity of the series is 43. Find the value of x.

[3]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)−3 < x < 13
|3x + 45| < 1 (M1)
−5 < 3x + 4 < 5 (A1)
−3 < x < 13 A1
3
(b)x = −1112
11 − r = 43 (M1)
r = 14 (A1)
3x + 4 = 54 ⇒ x = −1112 A1
3
Question 2Structured · 6 marks

The second term of a geometric sequence is −27 and the fifth term is 1.

(a)

Find the common ratio.

[3]
(b)

Find the sum to infinity of the sequence.

[3]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)r = −13
u1r = −27, u1r4 = 1 (M1)
r3 = −127 (A1)
r = −13 A1
3
(b)2434
u1 = 81 (A1)
S∞ = 811 − (−1/3) (M1)
2434 A1
3
Question 3Structured · 5 marks

In an arithmetic sequence, u4 = 17 and u9 = 47.

(a)

Find the common difference and the first term.

[3]
(b)

Find the sum of the first 30 terms.

[2]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)d = 6, u1 = −1
u1 + 3d = 17, u1 + 8d = 47 (M1)
d = 6 A1
u1 = −1 A1
3
(b)2580
S30 = 302(2(−1) + 29(6)) (M1)
2580 A1
2
Question 4Structured · 4 marks

Find the value of Σr=436(r − 7).

[4]
Show answers and mark scheme
PartAnswer and marking pointsMarks
429
recognising an arithmetic series with 33 terms (not 36) (M1)
first term −3, last term 29 (A1)(A1)
332(−3 + 29) = 429 A1
4
Question 5Structured · 14 marks

Offer A: a starting salary of $32000 with an increase of $2000 each year.
Offer B: a starting salary of $32000 with an increase of 4% each year.

(a)

Find the salary in year 8 for each offer.

[4]
(b)

Find the total amount earned over 20 years under each offer.

[4]
(c)

Find the first year in which the salary under Offer B is greater than the salary under Offer A.

[3]
(d)

Find the minimum number of complete years after which the total earned under Offer B exceeds the total earned under Offer A.

[3]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)A: $46000; B: $42110
A: 32000 + 7(2000) (M1)
$46000 A1
B: 32000(1.04)7 (M1)
$42110 A1
4
(b)A: $1020000; B: $952899
S20 = 202(2(32000) + 19(2000)) (M1)
$1020000 A1
S20 = 32000(1.0420 − 1)1.04 − 1 (M1)
$952899 A1
4
(c)year 24
32000(1.04)n−1 > 32000 + (n − 1)(2000) (M1)
attempt to solve, e.g. table or graph (M1)
year 24 A1
3
(d)33 years
equating or comparing the sums (M1)
attempt to solve (M1)
33 A1
3
Question 6Structured · 7 marksA* challenge

A ball is dropped from a height of 2 m. After each bounce it rises to 70% of the height from which it fell.

(a)

Find the height reached after the third bounce.

[2]
(b)

Find the number of bounces after which the ball first rises to less than 0.3 m.

[2]
(c)

Find the total distance travelled by the ball before it comes to rest.

[3]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)0.686 m
2(0.7)3 (M1)
0.686 m A1
2
(b)6
2(0.7)n < 0.3 (M1)
6 A1
2
(c)11.3 m
2 + 2 × 1.401 − 0.7 M1A1
11.3 m A1
3

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Original IB-style practice questions written for mentorriyaz.in. These are not IB past paper questions, and this site is not affiliated with or endorsed by the International Baccalaureate Organization. Updated 2026-11-04. Paper generator · mentorriyaz.in