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Sequences & series: IB Mathematics: Analysis & Approaches questions with answers Free Sequences & series questions for IB Mathematics: Analysis & Approaches (SL & HL), part of Number & algebra. Each question has the answer and the marking points an examiner would look for.
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Sequences & series practice questions Question 1 Structured · 6 marks A* challenge
Consider the infinite geometric series 1 + (3x + 4 5 ) + (3x + 4 5 )2 + (3x + 4 5 )3 + …
(a) Find the set of values of x for which the series has a finite sum.
[3] (b) The sum to infinity of the series is 4 3 . Find the value of x.
[3] Show answers and mark scheme Part Answer and marking points Marks (a) −3 < x < 1 3 |3x + 4 5 | < 1 (M1) −5 < 3x + 4 < 5 (A1) −3 < x < 1 3 A1
3 (b) x = −11 12 1 1 − r = 4 3 (M1) r = 1 4 (A1) 3x + 4 = 5 4 ⇒ x = −11 12 A1
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Question 2 Structured · 6 marks
The second term of a geometric sequence is −27 and the fifth term is 1.
(b) Find the sum to infinity of the sequence.
[3] Show answers and mark scheme Part Answer and marking points Marks (a) r = −1 3 u1 r = −27, u1 r4 = 1 (M1) r3 = −1 27 (A1) r = −1 3 A1
3 (b) 243 4 u1 = 81 (A1) S∞ = 81 1 − (−1/3) (M1) 243 4 A1
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Question 3 Structured · 5 marks
In an arithmetic sequence, u4 = 17 and u9 = 47.
(a) Find the common difference and the first term.
[3] (b) Find the sum of the first 30 terms.
[2] Show answers and mark scheme Part Answer and marking points Marks (a) d = 6, u1 = −1u1 + 3d = 17, u1 + 8d = 47 (M1) d = 6 A1 u1 = −1 A1
3 (b) 2580S30 = 30 2 (2(−1) + 29(6)) (M1) 2580 A1
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Question 4 Structured · 4 marks
Find the value of Σr=4 36 (r − 7).
Show answers and mark scheme Part Answer and marking points Marks 429recognising an arithmetic series with 33 terms (not 36) (M1) first term −3, last term 29 (A1)(A1) 33 2 (−3 + 29) = 429 A1
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Question 5 Structured · 14 marks
Offer A: a starting salary of $32000 with an increase of $2000 each year. Offer B: a starting salary of $32000 with an increase of 4% each year.
(a) Find the salary in year 8 for each offer.
[4] (b) Find the total amount earned over 20 years under each offer.
[4] (c) Find the first year in which the salary under Offer B is greater than the salary under Offer A.
[3] (d) Find the minimum number of complete years after which the total earned under Offer B exceeds the total earned under Offer A.
[3] Show answers and mark scheme Part Answer and marking points Marks (a) A: $46000; B: $42110A: 32000 + 7(2000) (M1) $46000 A1 B: 32000(1.04)7 (M1) $42110 A1
4 (b) A: $1020000; B: $952899S20 = 20 2 (2(32000) + 19(2000)) (M1) $1020000 A1 S20 = 32000(1.0420 − 1) 1.04 − 1 (M1) $952899 A1
4 (c) year 2432000(1.04)n−1 > 32000 + (n − 1)(2000) (M1) attempt to solve, e.g. table or graph (M1) year 24 A1
3 (d) 33 yearsequating or comparing the sums (M1) attempt to solve (M1) 33 A1
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Question 6 Structured · 7 marks A* challenge
A ball is dropped from a height of 2 m. After each bounce it rises to 70% of the height from which it fell.
(a) Find the height reached after the third bounce.
[2] (b) Find the number of bounces after which the ball first rises to less than 0.3 m.
[2] (c) Find the total distance travelled by the ball before it comes to rest.
[3] Show answers and mark scheme Part Answer and marking points Marks (a) 0.686 m2(0.7)3 (M1) 0.686 m A1
2 (b) 62(0.7)n < 0.3 (M1) 6 A1
2 (c) 11.3 m2 + 2 × 1.40 1 − 0.7 M1A1 11.3 m A1
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