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Sine & cosine rules: IB Mathematics: Analysis & Approaches questions with answers Free Sine & cosine rules questions for IB Mathematics: Analysis & Approaches (SL & HL), part of Geometry & trigonometry. Each question has the answer and the marking points an examiner would look for.
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Sine & cosine rules practice questions Question 1 Structured · 7 marks A* challenge
In triangle ABC, BC = 8.4 cm, AC = 10 cm and BÂC = 25°.
(a) Find the two possible values of AB̂C.
[4] (b) Find the difference between the areas of the two possible triangles.
[3] Show answers and mark scheme Part Answer and marking points Marks (a) 30.2° or 150°sin AB̂C 10 = sin 25° 8.4 (M1)(A1) 30.2° A1 180° − 30.2° = 150° A1
4 (b) 30.7 cm2 AĈB = 125° or 5.21° (A1) 1 2 (8.4)(10)sin C for each (M1) 30.7 cm2 A1
3
Question 2 Structured · 5 marks A* challenge
In triangle ABC, AB = 10 cm, BC = 8 cm and angle BAC = 35°.
Find the two possible values of angle ACB.
[5] Show answers and mark scheme Part Answer and marking points Marks 45.8°, 134°sine rule (M1) sin C = 10 sin 35° 8 (A1) 45.8° A1 recognizing the ambiguous case (M1) 134° A1
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Question 3 Structured · 7 marks
In triangle ABC, BC = 7 cm, AC = 10 cm and angle ACB = 40°.
(b) Find the area of the triangle.
[2] Show answers and mark scheme Part Answer and marking points Marks (a) 6.46 cmcosine rule (M1) correct substitution (A1) 6.46 cm A1
3 (b) 22.5 cm2 ½ab sin C (M1) 22.5 cm2 A1
2 (c) 84.1°sine rule (M1) 84.1° A1
2
Question 4 Structured · 7 marks
In triangle PQR, PQ = 6 cm, PR = 14 cm and QP̂R = 55°.
(b) Find the area of triangle PQR.
[2] Show answers and mark scheme Part Answer and marking points Marks (a) 11.6 cmQR2 = 62 + 142 − 2(6)(14)cos 55° (M1)(A1) QR = 11.6 cm A1
3 (b) 34.4 cm2 1 2 (6)(14)sin 55° (M1) 34.4 cm2 A1
2 (c) 100°sin PQ̂R 14 = sin 55° 11.6 (M1) 100° A1
2
Question 5 Structured · 8 marks A* challenge
A ship leaves port P and sails 15 km on a bearing of 050° to point A. It then sails 10 km on a bearing of 145° to point B.
(a) Find the size of angle PÂB.
[2] (c) Find the bearing of P from B.
[3] Show answers and mark scheme Part Answer and marking points Marks (a) 85°use of parallel north lines (M1) 85° A1
2 (b) 17.3 kmPB2 = 152 + 102 − 2(15)(10)cos 85° (M1)(A1) 17.3 km A1
3 (c) 265°sine rule or coordinates to find an angle at B or P (M1) correct angle (A1) 265.2° A1
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Question 6 Structured · 7 marks A* challenge
In triangle ABC, BC = 8.9 cm, AC = 11 cm and BÂC = 42°.
(a) Find the two possible values of AB̂C.
[4] (b) Find the difference between the areas of the two possible triangles.
[3] Show answers and mark scheme Part Answer and marking points Marks (a) 55.8° or 124°sin AB̂C 11 = sin 42° 8.9 (M1)(A1) 55.8° A1 180° − 55.8° = 124° A1
4 (b) 36.8 cm2 AĈB = 82.2° or 13.8° (A1) 1 2 (8.9)(11)sin C for each (M1) 36.8 cm2 A1
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Original IB-style practice questions written for mentorriyaz.in. These are not IB past paper questions, and this site is not affiliated with or endorsed by the International Baccalaureate Organization. Updated 2026-11-04. Paper generator · mentorriyaz.in