IB · Physics SL & HL · Topic

D Fields: IB Physics questions and answers

10 free IB Physics D Fields questions written in the style of IB Physics papers: 4 multiple-choice and 6 structured, each with its answer and mark scheme. 4 of them are A* challenge questions, built to catch the mistakes strong students still make.

This topic covers D.1 Gravitational fields, D.2 Electric & magnetic fields, D.3 Motion in electromagnetic fields, D.4 Induction. Work through the questions below, then generate a full D Fields paper with a fresh set every time.

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D Fields sub-topics

D Fields practice questions

Question 1Multiple choice · 1 markA* challenge

Point charges of +4 μC and +1 μC are 0.4 m apart.
What is the electric potential at the midpoint between them?

  1. A 1.1 × 105 V
  2. B 1.3 × 105 V
  3. C 2.2 × 105 V
  4. D 1.1 × 106 V
Show answer

Answer: C

Question 2Multiple choice · 1 mark

A coil of 500 turns and area 5 × 10−3 m2 is perpendicular to a magnetic field. The field changes uniformly from 0.1 T to 0.05 T in 0.02 s.
What is the magnitude of the average induced emf?

  1. A 0.0025 V
  2. B 0.013 V
  3. C 6.3 V
  4. D 13 V
Show answer

Answer: C

Question 3Multiple choice · 1 mark

The gravitational field strength at the Earth’s surface is g. What is the field strength at a height of 2R above the surface, where R is the radius of the Earth?

  1. A 0.037 g
  2. B 0.11 g
  3. C 0.25 g
  4. D 0.33 g
Show answer

Answer: B

Question 4Multiple choice · 1 mark

An electron is accelerated from rest through a potential difference of 500 V.
What is its final speed?

  1. A 3.1 × 105 m s−1
  2. B 9.4 × 106 m s−1
  3. C 1.3 × 107 m s−1
  4. D 1.8 × 107 m s−1
Show answer

Answer: C

Question 5Structured · 12 marksA* challenge

Electrons are accelerated from rest through a potential difference of 1000 V and then enter the region between two parallel plates, 4 cm apart and 5 cm long, moving parallel to the plates. The potential difference between the plates is 600 V.

(a)

Show that the speed of the electrons entering the plates is about 1.9 × 107 m s−1.

[2]
(b)

Calculate the electric field strength between the plates and the acceleration of an electron.

[2]
(c)

Determine the vertical deflection of an electron as it leaves the plates.

[3]
(d)

Describe the shape of the path between the plates and after it leaves them.

[2]
(e)

A magnetic field is applied so that the electrons pass through undeflected. Calculate the magnetic flux density and state its direction relative to the electric field.

[3]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)1.87 × 107 m s−1
eV = ½mv2 ✓
v = 1.87 × 107 m s−1 ✓
2
(b)15000 V m−1; 2.63 × 1015 m s−2
E = Vd = 15000 V m−1 ✓
a = eEm = 2.63 × 1015 m s−2 ✓
2
(c)9.38 mm
time between plates = Lv = 2.67 × 10−9 s ✓
y = ½at2 ✓
9.38 mm ✓
3
(d)parabola then straight line
parabolic between the plates (constant force perpendicular to initial velocity) ✓
straight line after leaving the field ✓
2
(e)8.0 × 10−4 T
eE = evB ✓
B = Ev = 8.0 × 10−4 T ✓
perpendicular to both the electric field and the velocity ✓
3
Question 6Structured · 7 marksA* challenge

A coil of 150 turns and area 4.0 × 10−3 m2 is perpendicular to a magnetic field of 0.20 T. The field falls uniformly to zero in 0.050 s. The resistance of the coil is 3.0 Ω.

(a)

Calculate the initial magnetic flux linkage.

[1]
(b)

Calculate the average induced emf.

[2]
(c)

Calculate the charge that flows around the coil.

[2]
(d)

State Lenz’s law and use it to describe the direction of the induced current.

[2]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)0.12 Wb
NBA = 0.12 Wb ✓
1
(b)2.4 V
ε = Δ(NΦ)/Δt ✓
= 2.4 V ✓
2
(c)0.040 C
I = 0.80 A ✓
Q = 0.80 × 0.050 = 0.040 C ✓
2
(d)opposes change
induced emf opposes the change that produces it ✓
current produces a field in the same direction as the original field (trying to maintain the flux) ✓
2
Question 7Structured · 8 marksA* challenge

A metal rod of length 0.30 m slides at a constant 2.0 m s−1 along two parallel conducting rails in a uniform vertical magnetic field of 0.60 T. The rails are connected by a resistor of 1 Ω.

(a)

Calculate the induced emf.

[1]
(b)

Calculate the current in the circuit.

[1]
(c)

Calculate the force needed to keep the rod moving at constant speed.

[2]
(d)

Show that the mechanical power supplied equals the electrical power dissipated.

[2]
(e)

Outline how Lenz’s law applies to this system.

[2]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)0.360 V
ε = BLv = 0.360 V ✓
1
(b)0.360 A
0.360 A ✓
1
(c)0.0648 N
F = BIL ✓
= 0.0648 N ✓
2
(d)0.130 W
P = Fv = 0.130 W ✓
I2R = 0.130 W, the same ✓
2
(e)induced current opposes motion
induced current flows in a direction to oppose the change producing it ✓
the force on the current-carrying rod opposes its motion, so work must be done ✓
2
Question 8Structured · 6 marks

A satellite orbits the Earth at a height of 400 km. Earth mass = 5.97 × 1024 kg, radius = 6.37 × 106 m.

(a)

Calculate the gravitational field strength at this height.

[2]
(b)

Calculate the orbital speed.

[2]
(c)

Explain why astronauts in the satellite appear weightless.

[2]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)8.7 N kg−1
g = GM/r2 ✓
8.7 N kg−1 ✓
2
(b)7.7 km s−1
v = √(GM/r) ✓
7.67 × 103 m s−1 ✓
2
(c)free fall together
astronaut and satellite are both in free fall ✓
with the same acceleration, so no contact force ✓
2
Question 9Structured · 5 marks

Ions of charge +e and mass 3.8 × 10−26 kg are accelerated through 2.0 kV and enter a magnetic field of 0.25 T at right angles.

(a)

Calculate the speed of the ions.

[2]
(b)

Calculate the radius of their path.

[2]
(c)

State why the kinetic energy of the ions does not change in the field.

[1]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)1.3 × 105 m s−1
qV = ½mv2 ✓
1.30 × 105 m s−1 ✓
2
(b)0.12 m
r = mv/qB ✓
0.12 m ✓
2
(c)force perpendicular to velocity
the magnetic force is perpendicular to the velocity, so no work is done ✓
1
Question 10Structured · 5 marks

An electron enters the region between two horizontal plates at 3.0 × 107 m s−1, moving parallel to the plates. The field between the plates is 1.0 × 104 V m−1 and the plates are 6.0 cm long.

(a)

Calculate the time the electron spends between the plates.

[1]
(b)

Calculate the vertical deflection of the electron.

[3]
(c)

State the shape of the path between the plates.

[1]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)2.0 × 10−9 s
0.060/3.0 × 107 = 2.0 × 10−9 s ✓
1
(b)3.5 mm
a = eE/m = 1.76 × 1015 m s−2 ✓
s = ½at2 ✓
= 3.5 × 10−3 m ✓
3
(c)parabola
parabolic ✓
1

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Frequently asked questions

What is in IB Physics D Fields?

In the SL & HL syllabus, D Fields covers D.1 Gravitational fields, D.2 Electric & magnetic fields, D.3 Motion in electromagnetic fields, D.4 Induction.

Where can I get D Fields questions with mark schemes?

This page has 10 D Fields questions with answers. For more, the free generator on mentorriyaz.in builds a new D Fields paper with a full mark scheme each time you click.

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Original IB-style practice questions written for mentorriyaz.in. These are not IB past paper questions, and this site is not affiliated with or endorsed by the International Baccalaureate Organization. Updated 2026-11-04. Paper generator · mentorriyaz.in