IGCSE · Additional Mathematics 0606 · Vectors & calculus

Differentiation: IGCSE Additional Mathematics questions with answers

Free Differentiation questions for IGCSE Additional Mathematics (0606), part of Vectors & calculus. Each question has the answer and the marking points an examiner would look for.

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Differentiation practice questions

Question 1Structured · 3 marksA* challenge

The radius of a circle increases at 0.5 cm/s. Find the rate of increase of the area when the radius is 10 cm.

[3]
Show answers and mark scheme
PartAnswer and marking pointsMarks
31.4 cm²/s
dA/dr = 2πr B1
chain rule M1
31.4 A1
3
Question 2Structured · 6 marks

A curve has equation y = 3x3 + 3x2 − x.

(a)

Find dydx.

[2]
(b)

Find the equation of the normal to the curve at the point where x = 3.

[4]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)9x2 + 6x − 1
Two terms correct B1
All correct B1
2
(b)y − 105 = −198(x − 3)
gradient of tangent = 98 M1
gradient of normal = −198 M1
point (3, 105) B1
Correct equation in any form A1
4
Question 3Structured · 6 marks

Differentiate with respect to x: (a) (4x + 1)5; (b) x2 ln x; (c) e4xx.

[6]
Show answers and mark scheme
PartAnswer and marking pointsMarks
chain/product/quotient
5(4x + 1)4 × 4 M1
20(4x + 1)4 A1
product rule M1
2x ln x + x A1
quotient rule M1
4xe4x − e4xx2 A1
6
Question 4Structured · 6 marks

A curve has equation y = x3 − 12x + 4.

(a)

Find the coordinates of the stationary points.

[4]
(b)

Determine the nature of each stationary point.

[2]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)(2, −12) and (−2, 20)
dydx = 3x2 − 12 M1
x = ±2 A1
substitute M1
(2, −12) and (−2, 20) A1
4
(b)minimum at x = 2, maximum at x = −2
d2ydx2 = 6x M1
both correct A1
2
Question 5Structured · 3 marksA* challenge

The radius of a circle increases at 0.2 cm/s. Find the rate of increase of the area when the radius is 4 cm.

[3]
Show answers and mark scheme
PartAnswer and marking pointsMarks
5.03 cm²/s
dA/dr = 2πr B1
chain rule M1
5.03 A1
3
Question 6Structured · 6 marks

A curve has equation y = 2x3 − 4x2 − x.

(a)

Find dydx.

[2]
(b)

Find the equation of the normal to the curve at the point where x = 3.

[4]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)6x2 − 8x − 1
Two terms correct B1
All correct B1
2
(b)y − 15 = −129(x − 3)
gradient of tangent = 29 M1
gradient of normal = −129 M1
point (3, 15) B1
Correct equation in any form A1
4

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Original Cambridge-style practice questions written for mentorriyaz.in. These are not Cambridge past paper questions, and this site is not affiliated with or endorsed by Cambridge University Press & Assessment. Updated 2026-11-04. Paper generator · mentorriyaz.in