Solve 4x − 1 = 8x × 2.
Show answers and mark scheme
| Part | Answer and marking points | Marks |
|---|---|---|
| x = −3 both sides as powers of 2 M1 2(x − 1) = 3(x) + 1 M1 −3 A1 | 3 |
Free Indices II questions for IGCSE Mathematics (0580), part of Algebra & graphs. Each question has the answer and the marking points an examiner would look for.
Generate a full Indices II worksheet →All Algebra & graphs questionsSolve 4x − 1 = 8x × 2.
| Part | Answer and marking points | Marks |
|---|---|---|
| x = −3 both sides as powers of 2 M1 2(x − 1) = 3(x) + 1 M1 −3 A1 | 3 |
Simplify x5 × x6.
Simplify (2y5)2.
Find the value of 1252/3.
| Part | Answer and marking points | Marks |
|---|---|---|
| (a) | x11 x11 B1 | 1 |
| (b) | 4y10 4y10 B2 B1 for one part correct | 2 |
| (c) | 25 ∛125 = 5 seen M1 25 A1 | 2 |
Solve 27x − 2 = 9x + 3 × 3−1.
| Part | Answer and marking points | Marks |
|---|---|---|
| x = 11 both sides as powers of 3 M1 3(x − 2) = 2(x + 3) − 1 M1 11 A1 | 3 |
Simplify x2 × x5.
Simplify (5y2)3.
Find the value of 1252/3.
| Part | Answer and marking points | Marks |
|---|---|---|
| (a) | x7 x7 B1 | 1 |
| (b) | 125y6 125y6 B2 B1 for one part correct | 2 |
| (c) | 25 ∛125 = 5 seen M1 25 A1 | 2 |
Solve 27x − 3 = 3x + 2 × 3.
| Part | Answer and marking points | Marks |
|---|---|---|
| x = 6 both sides as powers of 3 M1 3(x − 3) = x + 2 + 1 M1 6 A1 | 3 |
Simplify x5 × x2.
Simplify (5y5)3.
Find the value of 1252/3.
| Part | Answer and marking points | Marks |
|---|---|---|
| (a) | x7 x7 B1 | 1 |
| (b) | 125y15 125y15 B2 B1 for one part correct | 2 |
| (c) | 25 ∛125 = 5 seen M1 25 A1 | 2 |
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Meet Riyaz →Original Cambridge-style practice questions written for mentorriyaz.in. These are not Cambridge past paper questions, and this site is not affiliated with or endorsed by Cambridge University Press & Assessment. Updated 2026-11-04. Paper generator · mentorriyaz.in