IGCSE · Mathematics 0580 · Geometry

Similarity: IGCSE Mathematics questions with answers

Free Similarity questions for IGCSE Mathematics (0580), part of Geometry. Each question has the answer and the marking points an examiner would look for.

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Similarity practice questions

Question 1Structured · 5 marksA* challenge
(a)

Two bottles are mathematically similar. The surface areas of the bottles are 36 cm² and 225 cm².
The smaller bottle has a volume of 64 cm³.
Calculate the volume of the larger bottle.

[3]
(b)

A third bottle, also similar, has a volume of 512 cm³. Find the surface area of this bottle.

[2]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)1000 cm³
length scale factor 52 from √(225 ÷ 36) M1
× (52)3 M1
1000 A1
3
(b)144 cm²
volume scale 8, so length scale 2 M1
144 A1
2
Question 2Structured · 4 marks

Triangle ABC is similar to triangle PQR. AB = 6 cm, BC = 4 cm and PQ = 15 cm.

(a)

Calculate QR.

[2]
(b)

The area of triangle ABC is 23 cm². Calculate the area of triangle PQR.

[2]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)10 cm
scale factor 2.5 M1
10 A1
2
(b)143.75 cm²
× 2.52 M1
143.75 A1
2
Question 3Structured · 7 marksA* challenge

In triangle ABC, D is the point on AB with AD : DB = 1 : 2 and E is the point on AC with AE : EC = 1 : 2. The lines BE and CD meet at X.

(a)

Explain why DE is parallel to BC and find the ratio DE : BC.

[2]
(b)

Find the fraction of the area of triangle ABC that lies inside triangle XBC.

[5]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)triangle ADE is an enlargement of ABC, scale factor 1/3; DE : BC = 1 : 3
ADE similar to ABC (common angle, sides in ratio 1 : 3) M1
so DE ∥ BC and DE : BC = 1 : 3 A1
2
(b)12
triangles XDE and XCB are similar, ratio 1 : 3 M1
so EX : XB = 1 : 3 A1
area EBC = 23 area ABC (same height, base EC = 23AC) M1
area XBC = 34 area EBC M1
12 (allow any equivalent route, e.g. DX : XC = 1 : 3) A1
5
Question 4Structured · 9 marksA* challenge

A solid cone has base radius 12 cm and height 36 cm. A smaller cone of height 12 cm is cut off the top by a cut parallel to the base, leaving a frustum.
[Volume of a cone = ⅓πr²h]

(a)

Calculate the volume of the frustum.

[4]
(b)

Show that the volume of the frustum is 2627 of the volume of the original cone.

[2]
(c)

A mathematically similar frustum has a total surface area 4 times as large. It is made of a material with density 1.2 g/cm³. Calculate its mass in kilograms.

[3]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)5230 cm³
small cone is similar: radius 4 cm M1
large cone 5429 M1
small cone 201.1 M1
5230 cm³ A1
4
(b)1 − (13)3 = 2627
volume scale factor (1/3)3 = 127 M1
1 − 127 = 2627 A1
2
(c)50.2 kg
linear scale factor 2 M1
volume × 8 M1
50.2 kg A1
3
Question 5Structured · 4 marksA* challenge

In triangle ABC, D is a point on AB and E is a point on AC. DE is parallel to BC.
AD = 8 cm, DB = 5 cm, DE = 6 cm and AE = 4 cm.

(a)

Calculate BC.

[2]
(b)

Calculate EC.

[2]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)9.75 cm
scale factor 138 M1
9.75 A1
2
(b)2.5 cm
AC = 4 × 138 = 6.5 M1
2.5 A1
2
Question 6Structured · 5 marksA* challenge
(a)

Two bottles are mathematically similar. The surface areas of the bottles are 54 cm² and 150 cm².
The smaller bottle has a volume of 108 cm³.
Calculate the volume of the larger bottle.

[3]
(b)

A third bottle, also similar, has a volume of 864 cm³. Find the surface area of this bottle.

[2]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)500 cm³
length scale factor 53 from √(150 ÷ 54) M1
× (53)3 M1
500 A1
3
(b)216 cm²
volume scale 8, so length scale 2 M1
216 A1
2

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