Which reagent and condition convert propanoic acid into propanoyl chloride?
- A PCl5 at room temperature
- B Cl2, UV light
- C HCl(aq), heat
- D NaCl, concentrated H2SO4
Show answer
Answer: A
Free Carboxylic acids & derivatives questions for AS Level Chemistry (9701), part of Organic chemistry. Each question has the answer and the marking points an examiner would look for.
Generate a full Carboxylic Acids & Derivatives worksheet →All Organic chemistry questionsWhich reagent and condition convert propanoic acid into propanoyl chloride?
Answer: A
What is observed when ethanoic acid is added to sodium carbonate?
Answer: C
Which statement describes esterification?
Answer: C
1.50 g of a carboxylic acid, RCOOH, was dissolved in water and made up to 250 cm3. 25.0 cm3 portions needed 17.05 cm3 of 0.100 mol dm−3 sodium hydroxide.
Calculate the amount of acid in 250 cm3 of solution.
Calculate Mr of the acid and identify it.
Write an equation for the reaction of RCOOH with sodium carbonate.
Name the reagent that reduces the acid and the type of product formed.
| Part | Answer and marking points | Marks |
|---|---|---|
| (a) | 0.0171 mol n(NaOH) = 1.71 × 10−3 mol C1 × 10 = 0.0171 mol A1 | 2 |
| (b) | 88.0; butanoic acid Mr = 88.0 A1 butanoic acid, CH₃CH₂CH₂COOH A1 | 2 |
| (c) | 2RCOOH + Na₂CO₃ → 2RCOONa + H₂O + CO₂ 2RCOOH + Na₂CO₃ → 2RCOONa + H₂O + CO₂ B1 | 1 |
| (d) | LiAlH₄; primary alcohol LiAlH₄ (in dry ether) B1 primary alcohol B1 | 2 |
Carboxylic acids react to form esters and other derivatives.
Describe the conditions to make an ester from ethanoic acid and ethanol.
Name the ester formed and draw its structural formula.
| Part | Answer and marking points | Marks |
|---|---|---|
| (a) | conc H₂SO₄ catalyst; heat under reflux concentrated sulfuric acid catalyst B1 heat (under reflux) B1 | 2 |
| (b) | ethyl ethanoate; CH₃COOCH₂CH₃ ethyl ethanoate B1 CH₃COOCH₂CH₃ B1 | 2 |
1.00 mol of ethanoic acid and 1.20 mol of propan-1-ol were heated with a few drops of concentrated sulfuric acid until equilibrium was reached. The equilibrium mixture contained 0.55 mol of ester.
Name the ester formed and state the role of the sulfuric acid.
Calculate Kc for the reaction.
Give the products when the ester is heated with aqueous sodium hydroxide.
Explain why ethanoic acid is a stronger acid than ethanol.
| Part | Answer and marking points | Marks |
|---|---|---|
| (a) | propyl ethanoate; catalyst propyl ethanoate B1 catalyst B1 | 2 |
| (b) | 1.03 moles at equilibrium: acid 0.45, alcohol 0.65, ester and water 0.55 C1 Kc = [ester][water]/([acid][alcohol]) (volumes cancel) C1 = 1.03 A1 | 3 |
| (c) | sodium ethanoate and propan-1-ol sodium ethanoate B1 propan-1-ol B1 | 2 |
| (d) | carboxylate ion delocalised negative charge in the ethanoate ion is delocalised over two O atoms M1 so the anion is stabilised and H⁺ is lost more readily M1 | 2 |
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