Let g(x) = (3x2 − 1)3.
Find the gradient of the graph of g at the point where x = 1.
Show answers and mark scheme
| Part | Answer and marking points | Marks |
|---|---|---|
| 72 attempt to use the chain rule M1 g′(x) = 3(3x2 − 1)2 × 6x A1A1 g′(1) = 72 A1 | 4 |
Free Differentiation questions for IB Mathematics: Analysis & Approaches (SL & HL), part of Calculus. Each question has the answer and the marking points an examiner would look for.
Generate a full Differentiation worksheet →All Calculus questionsLet g(x) = (3x2 − 1)3.
Find the gradient of the graph of g at the point where x = 1.
| Part | Answer and marking points | Marks |
|---|---|---|
| 72 attempt to use the chain rule M1 g′(x) = 3(3x2 − 1)2 × 6x A1A1 g′(1) = 72 A1 | 4 |
Let f(x) = x2e−x.
Find f′(x).
Find the x-coordinates of the points on the graph of f where the gradient is zero.
| Part | Answer and marking points | Marks |
|---|---|---|
| (a) | xe−x(−x + 2) attempt to use the product rule M1 2xe−x − x2e−x A1A1 | 3 |
| (b) | x = 0, x = 2 f′(x) = 0 M1 e−x ≠ 0 R1 x = 0, x = 2 A1 | 3 |
Let g(x) = (3x2 + 1)5.
Find the gradient of the graph of g at the point where x = 1.
| Part | Answer and marking points | Marks |
|---|---|---|
| 7680 attempt to use the chain rule M1 g′(x) = 5(3x2 + 1)4 × 6x A1A1 g′(1) = 7680 A1 | 4 |
Let f(x) = ln xx, x > 0.
Show that f′(x) = 1 − ln xx2.
Find the exact x-coordinate of the maximum point of the graph of f.
| Part | Answer and marking points | Marks |
|---|---|---|
| (a) | shown attempt to use the quotient rule M1 x·[[1x − ln x|x2]] A1 simplifying to 1 − ln xx2 AG A1 | 3 |
| (b) | x = e ln x = 11 (M1) x = e A1 | 2 |
Let g(x) = (3x2 − 1)5.
Find the gradient of the graph of g at the point where x = 2.
| Part | Answer and marking points | Marks |
|---|---|---|
| 878460 attempt to use the chain rule M1 g′(x) = 5(3x2 − 1)4 × 6x A1A1 g′(2) = 878460 A1 | 4 |
Let f(x) = ln xx3, x > 0.
Show that f′(x) = 1 − 3ln xx4.
Find the exact x-coordinate of the maximum point of the graph of f.
| Part | Answer and marking points | Marks |
|---|---|---|
| (a) | shown attempt to use the quotient rule M1 x3·[[1x − 3x2ln x|x6]] A1 simplifying to 1 − 3ln xx4 AG A1 | 3 |
| (b) | x = e1/3 ln x = 13 (M1) x = e1/3 A1 | 2 |
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Meet Riyaz →Original IB-style practice questions written for mentorriyaz.in. These are not IB past paper questions, and this site is not affiliated with or endorsed by the International Baccalaureate Organization. Updated 2026-11-04. Paper generator · mentorriyaz.in