IB · Mathematics: Analysis & Approaches SL & HL · Functions

Transformations of graphs: IB Mathematics: Analysis & Approaches questions with answers

Free Transformations of graphs questions for IB Mathematics: Analysis & Approaches (SL & HL), part of Functions. Each question has the answer and the marking points an examiner would look for.

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Transformations of graphs practice questions

Question 1Structured · 4 marks

The graph of y = x2 is stretched vertically by scale factor 3 and then translated by 31. Write the equation of the new graph in the form y = ax2 + bx + c.

[4]
Show answers and mark scheme
PartAnswer and marking pointsMarks
y = 3x2 − 18x + 28
stretch: y = 3x2 A1
translation: y = 3(x − 3)2 + 1 M1A1
expanded correctly A1
4
Question 2Structured · 7 marks

The point P(4, 4) lies on the graph of y = f(x). The graph of y = f(x) is transformed to the graph of y = 2f(3x + 9) + 5.

(a)

Find the coordinates of the image of P.

[3]
(b)

Describe fully a sequence of transformations that maps the graph of y = f(x) onto this graph.

[4]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)(−53, 13)
3x + 9 = 4 (M1)
x = −53 A1
y = 13 A1
3
(b)horizontal stretch, scale factor 13, then horizontal translation of −3; vertical stretch, scale factor 2; vertical translation of 5
horizontal stretch, scale factor 13 A1
followed by a horizontal translation of −3 (or: translation of −9 first, then the stretch) A1
vertical stretch, scale factor 2 A1
vertical translation of 5 (after the vertical stretch) A1
4
Question 3Structured · 5 marks

The graph of y = f(x) passes through the point P(4, 2).

(a)

The graph of y = f(x) is translated by −2−1. Find the image of P.

[2]
(b)

The graph of y = f(x) is transformed to y = 3f(x − 1). Find the image of P.

[2]
(c)

Describe fully a transformation that maps y = f(x) onto y = f(−x).

[1]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)(2, 1)
x-coordinate 2 A1
y-coordinate 1 A1
2
(b)(5, 6)
x: 5 A1
y: 6 A1
2
(c)reflection in the y-axis
reflection in the y-axis A1
1
Question 4Structured · 4 marks

The graph of y = x2 is stretched vertically by scale factor 2 and then translated by 1−3. Write the equation of the new graph in the form y = ax2 + bx + c.

[4]
Show answers and mark scheme
PartAnswer and marking pointsMarks
y = 2x2 − 4x − 1
stretch: y = 2x2 A1
translation: y = 2(x − 1)2 − 3 M1A1
expanded correctly A1
4
Question 5Structured · 7 marks

The point P(−1, 4) lies on the graph of y = f(x). The graph of y = f(x) is transformed to the graph of y = −f(3x + 3) − 2.

(a)

Find the coordinates of the image of P.

[3]
(b)

Describe fully a sequence of transformations that maps the graph of y = f(x) onto this graph.

[4]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)(−43, −6)
3x + 3 = −1 (M1)
x = −43 A1
y = −6 A1
3
(b)horizontal stretch, scale factor 13, then horizontal translation of −1; reflection in the x-axis and no vertical stretch; vertical translation of −2
horizontal stretch, scale factor 13 A1
followed by a horizontal translation of −1 (or: translation of −3 first, then the stretch) A1
reflection in the x-axis and no vertical stretch A1
vertical translation of −2 (after the vertical stretch) A1
4
Question 6Structured · 5 marks

The graph of y = f(x) passes through the point P(1, 3).

(a)

The graph of y = f(x) is translated by 1−2. Find the image of P.

[2]
(b)

The graph of y = f(x) is transformed to y = 2f(x − 1). Find the image of P.

[2]
(c)

Describe fully a transformation that maps y = f(x) onto y = f(−x).

[1]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)(2, 1)
x-coordinate 2 A1
y-coordinate 1 A1
2
(b)(2, 6)
x: 2 A1
y: 6 A1
2
(c)reflection in the y-axis
reflection in the y-axis A1
1

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Original IB-style practice questions written for mentorriyaz.in. These are not IB past paper questions, and this site is not affiliated with or endorsed by the International Baccalaureate Organization. Updated 2026-11-04. Paper generator · mentorriyaz.in