IB · Mathematics: Applications & Interpretation SL & HL · Topic

Statistics & Probability: IB Mathematics: Applications & Interpretation questions and answers

10 free IB Mathematics: Applications & Interpretation Statistics & Probability questions written in the style of IB Mathematics: Applications & Interpretation papers, each with its answer and mark scheme. 2 of them are A* challenge questions, built to catch the mistakes strong students still make.

This topic covers Descriptive statistics, Correlation & regression, Probability, Binomial & normal distributions, χ² tests, t-tests, Poisson distribution, Markov chains, Confidence intervals, Hypothesis testing & errors. Work through the questions below, then generate a full Statistics & Probability paper with a fresh set every time.

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Statistics & probability sub-topics

Statistics & probability practice questions

Question 1Structured · 5 marksA* challenge

The table shows the scores of 32 students. The mean score is 2.75.

Score12345
Frequency6p8q4
Table 1.1

Find the values of p and q.

[5]
Show answers and mark scheme
PartAnswer and marking pointsMarks
p = 9, q = 5
p + q = 14 A1
Σfx: 6 + 2p + 24 + 4q + 20 = 88 A1
solving simultaneously (M1)
p = 9 A1
q = 5 A1
5
Question 2Structured · 7 marksA* challenge

For events A and B, P(A) = 0.4, P(B) = 0.4 and P(A | B) = 0.75.

(a)

Find P(A ∩ B).

[2]
(b)

Find P(A ∪ B).

[2]
(c)

Find P(B | A′).

[2]
(d)

Determine whether A and B are independent, giving a reason.

[1]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)0.300
P(A | B) × P(B) (M1)
0.300 A1
2
(b)0.500
P(A) + P(B) − P(A ∩ B) (M1)
0.500 A1
2
(c)0.167
P(B ∩ A′)P(A′) = 0.1000.600 (M1)
0.167 A1
2
(d)not independent
P(A | B) = 0.75 ≠ P(A) = 0.4, so not independent R1
1
Question 3Structured · 14 marks

Each year 20% of the customers of company X move to company Y, and 10% of the customers of company Y move to company X. Initially X has 2000 customers and Y has 2500.

(a)

Write down a transition matrix T for the movement of customers.

[2]
(b)

Find the eigenvalues and corresponding eigenvectors of T.

[4]
(c)

Hence write down matrices P and D such that T = PDP−1.

[2]
(d)

Find an expression for the number of customers of X after n years.

[5]
(e)

Write down the number of customers X can expect in the long term.

[1]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)0.8 0.10.2 0.9
columns sum to 1 (M1)
0.8 0.10.2 0.9 A1
2
(b)λ = 1, λ = 0.7
det(T − λI) = 0 (M1)
λ = 1, λ = 0.7 A1
eigenvector for 1: 0.10.2 (or a multiple) A1
eigenvector for 0.7: 1−1 A1
4
(c)P, D
P = 0.1 10.2 −1 A1
D = 1 00 0.7 A1
2
(d)1500 + 500(0.7)n
use of Tn = PDnP−1 M1
correct P−1 A1
xn = 1500 + 500(0.7)n A2
form A + B(λ)n A1
5
(e)1500
1500 A1
1
Question 4Structured · 5 marks

Two judges award scores to 6 contestants.

ContestantABCDEF
Judge 1615065705845
Judge 2685672756561
Table 4.1
(a)

Find Spearman’s rank correlation coefficient, rs.

[4]
(b)

Comment on the level of agreement between the judges.

[1]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)0.943
ranking both sets of scores (M1)
correct ranks A1
Pearson’s coefficient applied to the ranks (M1)
rs = 0.943 A1
4
(b)strong agreement
strong positive agreement R1
1
Question 5Structured · 6 marks

The probability that a seed germinates is 0.2. A packet contains 20 seeds.

(a)

Find the probability that exactly 4 seeds germinate.

[2]
(b)

Find the probability that more than 4 seeds germinate.

[2]
(c)

Find the expected number and the variance of the number of seeds that germinate.

[2]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)0.218
B(20, 0.2) (M1)
0.218 A1
2
(b)0.370
1 − P(X ≤ 4) (M1)
0.370 A1
2
(c)4, 3.2
E = 4 A1
Var = 3.2 A1
2
Question 6Structured · 13 marks

The volume of drink in bottles has mean 1000 ml and standard deviation 15 ml. The distribution of the volumes is not known.

(a)

A sample of 40 bottles is taken. State the approximate distribution of the sample mean X̄, giving a reason.

[3]
(b)

Find the probability that the sample mean is less than 999 ml.

[2]
(c)

A different sample of 40 bottles has mean 996 ml. Find a 95% confidence interval for the population mean, assuming σ = 15.

[3]
(d)

Hence comment on the claim that the mean volume is 1000 ml.

[2]
(e)

Find the least sample size needed for the width of a 95% confidence interval to be at most 4 ml.

[3]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)X̄ ~ N(1000, 5.63)
central limit theorem, n large R1
mean 1000 A1
variance 15240 = 5.63 A1
3
(b)0.337
normal CDF with standard error (M1)
0.337 A1
2
(c)991.4 < μ < 1001
z-interval (M1)
996 ± 1.96 × 15√40 (A1)
991.4 < μ < 1001 A1
3
(d)supported
1000 is in the interval R1
the claim is supported A1
2
(e)217
2 × 1.96 × 15√n ≤ 4 (M1)
solving for n (M1)
217 A1
3
Question 7Structured · 5 marks

The number of books read by a group of students last month is shown.

Books012345
Frequency91444107
Table 7.1
(a)

Find the mean and the standard deviation of the number of books read.

[3]
(b)

Find the median.

[2]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)mean 2.27, sd 1.79
GDC with frequencies (M1)
mean 2.27 A1
sd 1.79 A1
3
(b)2
48 values, median position 24.5 (M1)
2 A1
2
Question 8Structured · 6 marks

In a class of 54 students, 21 study French (F), 16 study Spanish (S) and 10 study both.

(a)

Find the number of students who study neither.

[1]
(b)

Find P(F ∪ S) and P(S | F).

[3]
(c)

Determine whether F and S are independent.

[2]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)27
27 A1
1
(b)2754, 1021
2754 A1
conditional on F (M1)
1021 A1
3
(c)not independent
P(F)P(S) = 0.115, P(F ∩ S) = 0.185 M1
not equal, so not independent A1
2
Question 9Structured · 5 marks

The lengths of a species of fish are normally distributed with mean 65 mm and standard deviation 12 mm.

(a)

Find the probability that a fish is longer than 77 mm.

[2]
(b)

8 fish are caught. Find the probability that exactly 2 are longer than 77 mm.

[3]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)0.159
normal CDF (M1)
0.159 A1
2
(b)0.250
X ~ B(8, 0.159) (M1)(A1)
0.250 A1
3
Question 10Structured · 4 marks

The masses of apples are normally distributed with mean 50 g and standard deviation 8 g.

(a)

Find the probability that an apple has mass between 42 g and 55 g.

[2]
(b)

Find the mass exceeded by 10% of apples.

[2]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)0.575
GDC normalcdf (M1)
0.575 A1
2
(b)60.3 g
inverse normal (M1)
60.3 A1
2

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What is in IB Mathematics: Applications & Interpretation Statistics & Probability?

In the SL & HL syllabus, Statistics & Probability covers Descriptive statistics, Correlation & regression, Probability, Binomial & normal distributions, χ² tests, t-tests, Poisson distribution, Markov chains, Confidence intervals, Hypothesis testing & errors.

Where can I get Statistics & Probability questions with mark schemes?

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Original IB-style practice questions written for mentorriyaz.in. These are not IB past paper questions, and this site is not affiliated with or endorsed by the International Baccalaureate Organization. Updated 2026-11-04. Paper generator · mentorriyaz.in