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Simultaneous equations: IGCSE Additional Mathematics questions with answers Free Simultaneous equations questions for IGCSE Additional Mathematics (0606), part of Algebra. Each question has the answer and the marking points an examiner would look for.
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Simultaneous equations practice questions Question 1 Structured · 6 marks A* challenge
The line y + 3x = 6 meets the curve xy = 3 at the points A and B.
Find the coordinates of A and B and the length of AB.
[6] Show answers and mark scheme Part Answer and marking points Marks (1, 3), (1, 3); 0substitute y = 6 − 3x M1 3x2 − 6x + 3 = 0 A1 solve M1 (1, 3) and (1, 3) A1 distance formula M1 0 A1
6
Question 2 Structured · 5 marks
Solve the simultaneous equations y = −2x − 3 x2 + y2 = 5
[5] Show answers and mark scheme Part Answer and marking points Marks (−2, 1) and (−2 5 , −11 5 )substitute to form a quadratic M1 5x2 + 12x + 4 = 0 A1 solve M1 x = −2, x = −2 5 A1 y = 1, y = −11 5 A1
5
Question 3 Structured · 2 marks
State what is meant by the term tangent condition.
[2] Show answers and mark scheme Part Answer and marking points Marks A line is a tangent to a curve when the resulting quadratic has a discriminant of zeroA line is a tangent to a curve when the resulting quadratic has a discriminant of zero B2
2
Question 4 Structured · 6 marks A* challenge
The line y + 4x = 8 meets the curve xy = 4 at the points A and B.
Find the coordinates of A and B and the length of AB.
[6] Show answers and mark scheme Part Answer and marking points Marks (1, 4), (1, 4); 0substitute y = 8 − 4x M1 4x2 − 8x + 4 = 0 A1 solve M1 (1, 4) and (1, 4) A1 distance formula M1 0 A1
6
Question 5 Structured · 5 marks
Solve the simultaneous equations y = x − 3 x2 + y2 = 45
[5] Show answers and mark scheme Part Answer and marking points Marks (−3, −6) and (6, 3)substitute to form a quadratic M1 2x2 − 6x − 36 = 0 A1 solve M1 x = −3, x = 6 A1 y = −6, y = 3 A1
5
Question 6 Structured · 6 marks A* challenge
The line y + 2x = 4 meets the curve xy = 2 at the points A and B.
Find the coordinates of A and B and the length of AB.
[6] Show answers and mark scheme Part Answer and marking points Marks (1, 2), (1, 2); 0substitute y = 4 − 2x M1 2x2 − 4x + 2 = 0 A1 solve M1 (1, 2) and (1, 2) A1 distance formula M1 0 A1
6
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Original Cambridge-style practice questions written for mentorriyaz.in. These are not Cambridge past paper questions, and this site is not affiliated with or endorsed by Cambridge University Press & Assessment. Updated 2026-11-04. Paper generator · mentorriyaz.in