IGCSE · Additional Mathematics 0606 · Algebra

Simultaneous equations: IGCSE Additional Mathematics questions with answers

Free Simultaneous equations questions for IGCSE Additional Mathematics (0606), part of Algebra. Each question has the answer and the marking points an examiner would look for.

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Simultaneous equations practice questions

Question 1Structured · 6 marksA* challenge

The line y + 3x = 6 meets the curve xy = 3 at the points A and B.

Find the coordinates of A and B and the length of AB.

[6]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(1, 3), (1, 3); 0
substitute y = 6 − 3x M1
3x2 − 6x + 3 = 0 A1
solve M1
(1, 3) and (1, 3) A1
distance formula M1
0 A1
6
Question 2Structured · 5 marks

Solve the simultaneous equations
y = −2x − 3
x2 + y2 = 5

[5]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(−2, 1) and (−25, −115)
substitute to form a quadratic M1
5x2 + 12x + 4 = 0 A1
solve M1
x = −2, x = −25 A1
y = 1, y = −115 A1
5
Question 3Structured · 2 marks

State what is meant by the term tangent condition.

[2]
Show answers and mark scheme
PartAnswer and marking pointsMarks
A line is a tangent to a curve when the resulting quadratic has a discriminant of zero
A line is a tangent to a curve when the resulting quadratic has a discriminant of zero B2
2
Question 4Structured · 6 marksA* challenge

The line y + 4x = 8 meets the curve xy = 4 at the points A and B.

Find the coordinates of A and B and the length of AB.

[6]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(1, 4), (1, 4); 0
substitute y = 8 − 4x M1
4x2 − 8x + 4 = 0 A1
solve M1
(1, 4) and (1, 4) A1
distance formula M1
0 A1
6
Question 5Structured · 5 marks

Solve the simultaneous equations
y = x − 3
x2 + y2 = 45

[5]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(−3, −6) and (6, 3)
substitute to form a quadratic M1
2x2 − 6x − 36 = 0 A1
solve M1
x = −3, x = 6 A1
y = −6, y = 3 A1
5
Question 6Structured · 6 marksA* challenge

The line y + 2x = 4 meets the curve xy = 2 at the points A and B.

Find the coordinates of A and B and the length of AB.

[6]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(1, 2), (1, 2); 0
substitute y = 4 − 2x M1
2x2 − 4x + 2 = 0 A1
solve M1
(1, 2) and (1, 2) A1
distance formula M1
0 A1
6

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Original Cambridge-style practice questions written for mentorriyaz.in. These are not Cambridge past paper questions, and this site is not affiliated with or endorsed by Cambridge University Press & Assessment. Updated 2026-11-04. Paper generator · mentorriyaz.in