IGCSE · Additional Mathematics 0606 · Topic

Algebra: IGCSE Additional Mathematics questions and answers

10 free IGCSE Additional Mathematics Algebra questions written in the style of Cambridge Additional Mathematics papers, each with its answer and mark scheme. 4 of them are A* challenge questions, built to catch the mistakes strong students still make.

This topic covers Functions, Quadratic functions, Factors of polynomials, Equations, inequalities & graphs, Simultaneous equations, Logarithmic & exponential functions. Work through the questions below, then generate a full Algebra paper with a fresh set every time.

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Algebra sub-topics

Algebra practice questions

Question 1Structured · 4 marksA* challenge

Find the set of values of m for which the line y = mx − 7 does not meet the curve y = x2 + 18.

[4]
Show answers and mark scheme
PartAnswer and marking pointsMarks
−10 < m < 10
x2 − mx + 25 = 0 M1
b2 − 4ac < 0 M1
critical values ±10 A1
−10 < m < 10 A1
4
Question 2Structured · 3 marksA* challenge

The cubic equation x3 − 3x2 − x + 3 = 0 has a root x = 3.

Find the other two roots.

[3]
Show answers and mark scheme
PartAnswer and marking pointsMarks
−1, 1
divide by (x − 3) M1
quadratic factor A1
−1, 1 A1
3
Question 3Structured · 6 marksA* challenge

The line y + 2x = 4 meets the curve xy = 2 at the points A and B.

Find the coordinates of A and B and the length of AB.

[6]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(1, 2), (1, 2); 0
substitute y = 4 − 2x M1
2x2 − 4x + 2 = 0 A1
solve M1
(1, 2) and (1, 2) A1
distance formula M1
0 A1
6
Question 4Structured · 4 marksA* challenge

Variables x and y are related by y = axn. When lg y is plotted against lg x, a straight line is obtained with gradient 2.5 and intercept 0.477 on the lg y axis.

Find the values of a and n, and hence find y when x = 4.

[4]
Show answers and mark scheme
PartAnswer and marking pointsMarks
a = 3, n = 2.5; y = 96
lg y = n lg x + lg a M1
n = 2.5 A1
a = 3 A1
y = 96 A1
4
Question 5Structured · 5 marks

The number of bacteria, N, in a culture after t hours is given by N = 800e0.05t.

(a)

Find the initial number of bacteria.

[1]
(b)

Find the number of bacteria after 30 hours.

[1]
(c)

Find the time taken for the number to reach 2400.

[3]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)800
800 B1
1
(b)3585
3585 B1
1
(c)22 hours
e0.05t = 3 M1
take ln M1
22 A1
3
Question 6Structured · 3 marks

Find the values of k for which the line y = kx + 4 is a tangent to the curve y = x2 + 20.

[3]
Show answers and mark scheme
PartAnswer and marking pointsMarks
k = ±8
x2 − kx + 16 = 0 M1
b2 − 4ac = 0: k2 = 64 M1
k = ±8 A1
3
Question 7Structured · 5 marks

f(x) = (x + 3)2 + 5 for x ≥ −3

(a)

State the range of f.

[1]
(b)

Find f−1(x) and state its domain.

[3]
(c)

Describe how the graphs of y = f(x) and y = f−1(x) are related.

[1]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)f(x) ≥ 5
f(x) ≥ 5 B1
1
(b)−3 + √(x − 5), x ≥ 5
swap x and y and rearrange M1
f−1(x) = √(x − 5) − 3 A1
domain x ≥ 5 B1
3
(c)reflection in y = x
reflection in the line y = x B1
1
Question 8Structured · 7 marks

p(x) = x3 + ax2 + bx − 48
It is given that x + 4 is a factor of p(x) and that when p(x) is divided by x − 1 the remainder is −60.

(a)

Find the values of a and b.

[4]
(b)

Factorise p(x) completely.

[2]
(c)

Hence solve p(x) = 0.

[1]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)a = 3, b = −16
p(−4) = 0 used M1
p(1) = −60 used M1
Solve simultaneously M1
a = 3, b = −16 A1
4
(b)(x + 4)(x + 3)(x − 4)
Quadratic factor found M1
Complete factorisation A1
2
(c)−4, −3, 4
−4, −3, 4 B1
1
Question 9Structured · 8 marks
(a)

Solve log3 x + log3 (x + 8) = 2.

[4]
(b)

Solve 22x − 10 × 2x + 16 = 0.

[4]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)x = 1
log3 x(x + 8) = 2 M1
x2 + 8x − 9 = 0 M1
Solve quadratic M1
x = 1 only (reject negative root) A1
4
(b)x = 1, x = 3
Let y = 2x: y2 − 10y + 16 = 0 M1
y = 2, y = 8 A1
Convert back M1
x = 1, x = 3 A1
4
Question 10Structured · 5 marks

Solve the simultaneous equations
y = −x − 4
x2 + y2 = 40

[5]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(2, −6) and (−6, 2)
substitute to form a quadratic M1
2x2 + 8x − 24 = 0 A1
solve M1
x = 2, x = −6 A1
y = −6, y = 2 A1
5

Other IGCSE Additional Mathematics topics

Frequently asked questions

What is in IGCSE Additional Mathematics Algebra?

In the 0606 syllabus, Algebra covers Functions, Quadratic functions, Factors of polynomials, Equations, inequalities & graphs, Simultaneous equations, Logarithmic & exponential functions.

Where can I get Algebra questions with mark schemes?

This page has 10 Algebra questions with answers. For more, the free generator on mentorriyaz.in builds a new Algebra paper with a full mark scheme each time you click.

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Original Cambridge-style practice questions written for mentorriyaz.in. These are not Cambridge past paper questions, and this site is not affiliated with or endorsed by Cambridge University Press & Assessment. Updated 2026-11-04. Paper generator · mentorriyaz.in