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Straight-line graphs: IGCSE Additional Mathematics questions with answers Free Straight-line graphs questions for IGCSE Additional Mathematics (0606), part of Geometry & trigonometry. Each question has the answer and the marking points an examiner would look for.
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Straight-line graphs practice questions Question 1 Structured · 5 marks A* challenge
The points A(−2, 1), B(6, 5) and C(4, k) are such that angle ABC = 90°.
(b) Find the area of triangle ABC.
[2] Show answers and mark scheme Part Answer and marking points Marks (a) k = 9gradient AB = ½ B1 gradient BC = −2: (k − 5) ÷ (4 − 6) = −2 M1 k = 9 A1
3 (b) 20AB = √80, BC = √20 M1 ½ × √80 × √20 = 20 A1
2
Question 2 Structured · 4 marks
A is (−1, 0) and B is (5, 2).
Find the equation of the perpendicular bisector of AB, giving your answer in the form ax + by = c, where a, b and c are integers.
[4] Show answers and mark scheme Part Answer and marking points Marks 6x + 2y = 14midpoint (2, 1) B1 gradient AB = 1 3 B1 perpendicular gradient −3 M1 6x + 2y = 14 (or a multiple) A1
4
Question 3 Structured · 1 mark
State what is meant by the term gradient of perpendicular lines.
[1] Show answers and mark scheme Part Answer and marking points Marks Two lines are perpendicular when the product of their gradients is −1Two lines are perpendicular when the product of their gradients is −1 B1
1
Question 4 Structured · 4 marks
A is (−2, 2) and B is (0, −4).
Find the equation of the perpendicular bisector of AB, giving your answer in the form ax + by = c, where a, b and c are integers.
[4] Show answers and mark scheme Part Answer and marking points Marks 2x − 6y = 4midpoint (−1, −1) B1 gradient AB = −3 B1 perpendicular gradient 1 3 M1 2x − 6y = 4 (or a multiple) A1
4
Question 5 Structured · 4 marks
A is (−3, 1) and B is (1, −1).
Find the equation of the perpendicular bisector of AB, giving your answer in the form ax + by = c, where a, b and c are integers.
[4] Show answers and mark scheme Part Answer and marking points Marks 4x − 2y = −4midpoint (−1, 0) B1 gradient AB = −1 2 B1 perpendicular gradient 2 M1 4x − 2y = −4 (or a multiple) A1
4
Question 6 Structured · 4 marks
A is (−3, −1) and B is (−1, 3).
Find the equation of the perpendicular bisector of AB, giving your answer in the form ax + by = c, where a, b and c are integers.
[4] Show answers and mark scheme Part Answer and marking points Marks 2x + 4y = 0midpoint (−2, 1) B1 gradient AB = 2 B1 perpendicular gradient −1 2 M1 2x + 4y = 0 (or a multiple) A1
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Original Cambridge-style practice questions written for mentorriyaz.in. These are not Cambridge past paper questions, and this site is not affiliated with or endorsed by Cambridge University Press & Assessment. Updated 2026-11-04. Paper generator · mentorriyaz.in