IGCSE · Physics 0625 · Thermal physics

Melting, boiling & evaporation: IGCSE Physics questions with answers

Free Melting, boiling & evaporation questions for IGCSE Physics (0625), part of Thermal physics. Each question has the answer and the marking points an examiner would look for.

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Melting, boiling & evaporation practice questions

Question 1Multiple choice · 1 markA* challenge

What is the energy needed to change 0.4 kg of ice at 0 °C into water at 40 °C?
(specific latent heat of fusion of ice = 3.34 × 105 J/kg; specific heat capacity of water = 4200 J/(kg °C))

  1. A 67 200 J
  2. B 1.34 × 105 J
  3. C 2.01 × 105 J
  4. D 3.02 × 105 J
Show answer

Answer: C

Question 2Multiple choice · 1 mark

Which statement describes melting point?

  1. A The increase in size of a material when its temperature rises
  2. B The change from liquid to gas that occurs throughout the liquid at a fixed temperature
  3. C A wire connecting the metal case of an appliance to earth so that a fault current flows safely to the ground
  4. D The temperature at which a solid changes to a liquid
Show answer

Answer: D

Question 3Structured · 9 marksA* challenge

An electric kettle has a power of 2000 W. It contains 0.8 kg of water at 25 °C. The specific heat capacity of water is 4200 J/(kg °C) and the specific latent heat of vaporisation of water is 2.26 × 106 J/kg. Assume that all the energy supplied is transferred to the water.

(a)

Calculate the time taken for the water to reach its boiling point.

[3]
(b)

The kettle does not switch off. Calculate the extra time needed for 0.05 kg of the water to boil away.

[2]
(c)

The temperature of the water does not rise while it is boiling, even though energy is still being supplied. Explain why.

[2]
(d)

In a real test the water takes 145 s to reach boiling point. Calculate the efficiency of the kettle.

[2]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)126 s
E = mcΔθ = 0.8 × 4200 × 75 C1
= 2.52 × 105 J; t = E ÷ P C1
126 A1
3
(b)56.5 s
E = mL = 0.05 × 2.26 × 106 C1
56.5 A1
2
(c)Energy is used to break the forces/bonds between molecules (increase potential energy), not to increase their kinetic energy
energy used to overcome forces of attraction between molecules B1
average kinetic energy of molecules (and so temperature) does not change B1
2
(d)87%
useful energy ÷ total energy = 2.52 × 105 ÷ (2000 × 145) C1
87 A1
2
Question 4Structured · 10 marks

This question is about changes of state.

(a)

Describe the arrangement and motion of particles in a solid and in a liquid.

[3]
(b)

A beaker of ice is heated steadily. Explain why the temperature stays at 0 °C while the ice melts.

[2]
(c)

State two differences between boiling and evaporation.

[2]
(d)

Explain, in terms of particles, why evaporation cools the liquid that is left.

[3]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)solid: regular, vibrate in fixed positions; liquid: close, irregular, move past each other
solid: particles close together in a regular pattern B1
vibrate about fixed positions B1
liquid: close together but randomly arranged and able to move past each other B1
3
(b)energy used to break bonds between particles, not to increase kinetic energy
the energy supplied is used to overcome forces between the particles / break bonds B1
so the kinetic energy (temperature) of the particles does not increase B1
2
(c)boiling at one temperature, throughout the liquid; evaporation at any temperature, surface only
boiling occurs at a specific temperature, evaporation at any temperature B1
boiling happens throughout the liquid, evaporation only at the surface B1
2
(d)most energetic particles escape; average kinetic energy of remaining particles falls; lower temperature
the most energetic molecules escape from the surface B1
the average kinetic energy of the remaining molecules decreases B1
so the temperature falls B1
3
Question 5Structured · 4 marks

Wet clothes are hung outside to dry.

(a)

State two conditions that make clothes dry quickly.

[2]
(b)

Explain why the clothes dry faster on a windy day.

[2]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)warm; windy; low humidity; spread out
Any 2 of: warm temperature; windy; low humidity; large surface area (spread out) B2
2
(b)wind removes vapour, maintains gradient
wind carries away the water vapour B1
so more molecules can escape from the surface B1
2
Question 6Structured · 5 marks

After swimming, a person standing in a breeze feels cold, even on a warm day.

(a)

Explain why.

[3]
(b)

State two factors that increase the rate of evaporation.

[2]
Show answers and mark scheme
PartAnswer and marking pointsMarks
(a)evaporation cools the skin
water evaporates from the skin B1
the most energetic molecules escape B1
the remaining water and skin are cooled B1
3
(b)higher temperature; larger surface area; air movement
Any 2 of: higher temperature; larger surface area; moving air (wind) over the surface; lower humidity B2
2

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Original Cambridge-style practice questions written for mentorriyaz.in. These are not Cambridge past paper questions, and this site is not affiliated with or endorsed by Cambridge University Press & Assessment. Updated 2026-11-04. Paper generator · mentorriyaz.in