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Indices I: IGCSE Mathematics questions with answers Free Indices I questions for IGCSE Mathematics (0580), part of Number. Each question has the answer and the marking points an examiner would look for.
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Indices I practice questions Question 1 Structured · 9 marks A* challenge
Do not use a calculator in this question.
(a) Find the last two digits of 72026 .
[5] (b) Find the last two digits of 32026 + 72026 .
[4] Show answers and mark scheme Part Answer and marking points Marks (a) 4972 = 49, 74 = 2401 M1 74 ends in 01, so 74k ends in 01 M1 2026 = 4 × 506 + 2 M1 72026 = (74 )506 × 49 M1 last two digits 49 A1
5 (b) 78finds a power of 3 ending in 01 (320 ) M1 2026 = 20 × 101 + 6 M1 32026 ends in 29 (36 = 729) A1 29 + 49 = 78 A1
4
Question 2 Structured · 3 marks A* challenge
Solve 4x + 1 = 2x + 2 × 22 .
[3] Show answers and mark scheme Part Answer and marking points Marks x = 2both sides as powers of 2 M1 2(x + 1) = x + 2 + 2 M1 2 A1
3
Question 3 Structured · 5 marks
(c) Find the value of 27−1/3 .
[2] Show answers and mark scheme Part Answer and marking points Marks (a) x5 x5 B1
1 (b) 125y9 125y9 B2 B1 for one part correct
2 (c) 1 3 ∛27 = 3 seen M1 1 3 A1
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Question 4 Structured · 3 marks A* challenge
Solve 3x + 2 = 9x + 3 × 33 .
[3] Show answers and mark scheme Part Answer and marking points Marks x = −7both sides as powers of 3 M1 1(x + 2) = 2(x + 3) + 3 M1 −7 A1
3
Question 5 Structured · 5 marks
(c) Find the value of 64−2/3 .
[2] Show answers and mark scheme Part Answer and marking points Marks (a) x8 x8 B1
1 (b) 4y6 4y6 B2 B1 for one part correct
2 (c) 1 16 ∛64 = 4 seen M1 1 16 A1
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Question 6 Structured · 3 marks A* challenge
Solve 27x = 3x − 1 × 3−1 .
[3] Show answers and mark scheme Part Answer and marking points Marks x = −1both sides as powers of 3 M1 3(x) = x − 1 − 1 M1 −1 A1
3
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Original Cambridge-style practice questions written for mentorriyaz.in. These are not Cambridge past paper questions, and this site is not affiliated with or endorsed by Cambridge University Press & Assessment. Updated 2026-11-04. Paper generator · mentorriyaz.in