Standard form: IGCSE Mathematics questions with answers
Free Standard form questions for IGCSE Mathematics (0580), part of Number. Each question has the answer and the marking points an examiner would look for.
Find the number of digits in 1625 × 12530 when it is written out in full.
[3]
(b)
p and q are positive integers with p + q = 30. When 2p × 5q is written out in full, it has exactly 15 digits and its first digit is 1. Find p and q. Show that there are no other possibilities.
[5]
(c)
p and q are positive integers with p + q = 30. Find, in standard form, the largest value of 2p × 5q that has fewer than 15 digits.
[3]
Show answers and mark scheme
Part
Answer and marking points
Marks
(a)
94
2100 × 590M1 = 210 × 1090 = 1024 × 1090M1 94 A1
3
(b)
p = 17, q = 13
2p × 5q = 1015 × (25)p − 15M1 15 digits: 1014 ≤ number < 1015, so 0.1 ≤ (25)p − 15 < 1 M1 p − 15 = 1 or 2 only (0.4, 0.16; 0.064 < 0.1) A1 p = 16 gives 4 × 1014, first digit 4 M1 p = 17 gives 1.6 × 1014: p = 17, q = 13 A1
5
(c)
6.4 × 1013
2p × 5q decreases as p increases, so the least p with fewer than 15 digits is needed: p = 18 M1 218 × 512 = 26 × 1012M1 6.4 × 1013A1
3
Question 2Structured · 2 marks
Calculate (1.8 × 106) ÷ (2 × 103). Give your answer in standard form.
[2]
Show answers and mark scheme
Part
Answer and marking points
Marks
9 × 102
9 and 102 seen M1 9 × 102A1
2
Question 3Structured · 2 marks
Calculate (3.6 × 105) ÷ (4 × 104). Give your answer in standard form.
[2]
Show answers and mark scheme
Part
Answer and marking points
Marks
9 × 100
9 and 100 seen M1 9 × 100A1
2
Question 4Structured · 2 marks
Calculate (4 × 108) ÷ (5 × 10−4). Give your answer in standard form.
[2]
Show answers and mark scheme
Part
Answer and marking points
Marks
8 × 1011
8 and 1011 seen M1 8 × 1011A1
2
Question 5Structured · 2 marks
Calculate (3.6 × 107) ÷ (9 × 10−1). Give your answer in standard form.
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