Differentiation: A Level Mathematics questions with answers
Free Differentiation questions for A Level Mathematics (9709), part of Pure Mathematics 3. Each question has the answer and the marking points an examiner would look for.
Find the coordinates of the points on the curve where the tangent is parallel to the x-axis.
[4]
(c)
Find the coordinates of the points where the tangent is parallel to the y-axis.
[2]
Show answers and mark scheme
Part
Answer and marking points
Marks
(a)
2x + y + xdydx + 2ydydx = 0
implicit differentiation of y2B1 product rule on xy M1 rearranged correctly A1
3
(b)
(2, −4) and (−2, 4)
2x + y = 0 M1 substitute y = −2x into the curve M1 3x2 = 12 A1 (2, −4) and (−2, 4) A1
4
(c)
(−4, 2) and (4, −2)
x + 2y = 0 used M1 both points A1
2
Question 2Structured · 13 marksA* challenge
A curve is defined by the parametric equations x = 3t2, y = 2t3. The point P on the curve has parameter p, where p ≠ 0.
(a)
Show that the equation of the tangent at P is y = px − p3.
[2]
(b)
The tangent at P meets the curve again at Q. Find the parameter of Q in terms of p.
[3]
(c)
Find the values of p for which the tangent at P is also the normal to the curve at Q.
[2]
(d)
For the positive value of p, find the exact length of PQ.
[2]
(e)
For the positive value of p, find the exact area of the region enclosed by the line PQ and the curve.
[4]
Show answers and mark scheme
Part
Answer and marking points
Marks
(a)
dydx = 6t26t = t
dydx = 6t26t = t B1 y − 2p3 = p(x − 3p2) simplified A1
2
(b)
t = −p2
substitute x = 3t2, y = 2t3 into the tangent: 2t3 − 3pt2 + p3 = 0 M1 t = p is a repeated root: (t − p)2(2t + p) = 0 M1 t = −p2A1
3
(c)
p = ±√2
gradient at Q is −p2, so p × (−p2) = −1 M1 p = ±√2 A1
2
(d)
9√32
P(6, 4√2), Q(32, −√22) M1 PQ = 9√32A1
2
(e)
81√240
area under curve = ∫ y dxdt dt = ∫ 12t4 dt with limits −√22 and √2 (signed) M1 125t5 evaluated: 125(4√2 + √28) = 99√210A1 area under the line PQ between x = 32 and x = 6 (trapezium, signed) = 63√28M1 99√210 − 63√28 = 81√240A1
4
Question 3Structured · 4 marks
A curve has equation x2 + 3xy + y2 = 5. Find the gradient of the curve at the point (1, 1).
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