Astronomy and cosmology
Luminosity and radiant flux intensity, standard candles, Wien's displacement law and the Stefan–Boltzmann law to find stellar temperatures and radii, redshift, Hubble's law and the evidence for an expanding universe.
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In 30 seconds
- Luminosity L is the total power a star emits. At distance d, the radiant flux intensity is F = L/(4πd²): an inverse-square law.
- Standard candles (Cepheid variables, type 1a supernovae) have known luminosity, so measuring F gives d.
- Wien's law λmaxT = 2.9 × 10⁻³ m K gives T; Stefan–Boltzmann L = 4πσr²T⁴ then gives the radius r.
- Redshift Δλ/λ ≈ v/c. Distant galaxies are receding, and Hubble's law v = H₀d shows the universe is expanding: evidence for the Big Bang.
By the end you can
- Define luminosity and radiant flux intensity, and use F = L/(4πd²).
- Understand standard candles and use them to find distances.
- Use Wien's law and the Stefan–Boltzmann law to find surface temperatures and radii of stars.
- Use Δλ/λ ≈ Δf/f ≈ v/c and Hubble's law, and explain the evidence for an expanding universe.
1Luminosity and distance
The inverse-square law
Luminosity — the total radiant power emitted by a star.
Radiant flux intensity — the radiant power passing normally through unit area.
Standard candle — an astronomical object of known luminosity.
The Sun's luminosity is 3.83 × 10²⁶ W and it is 1.50 × 10¹¹ m away. Find the radiant flux intensity at the Earth.
- F = 3.83 × 10²⁶/(4π × (1.50 × 10¹¹)²) C1
- F = 1.35 × 10³ W m⁻² A1
A Cepheid of luminosity 1.0 × 10³⁰ W gives F = 2.0 × 10⁻¹² W m⁻² at the Earth. Find its distance.
- d = √(L/(4πF)) = √(1.0 × 10³⁰/(4π × 2.0 × 10⁻¹²)) C1
- d = 2.0 × 10²⁰ m A1
2Stellar temperatures and radii
Wien and Stefan–Boltzmann
A star's spectrum peaks at 350 nm and its luminosity is 4.0 × 10²⁸ W. Find its surface temperature and radius.
- T = 2.9 × 10⁻³/350 × 10⁻⁹ = 8300 K C1 A1
- r = √(L/(4πσT⁴)) = √(4.0 × 10²⁸/(4π × 5.67 × 10⁻⁸ × 8290⁴)) C1
- r = 3.5 × 10⁹ m A1
3The expanding universe
Redshift and Hubble's law
A hydrogen line emitted at 656.3 nm is observed at 669.4 nm from a galaxy. Find its recession speed and its distance (H₀ = 2.3 × 10⁻¹⁸ s⁻¹).
- v = c Δλ/λ = 3.00 × 10⁸ × 13.1/656.3 = 6.0 × 10⁶ m s⁻¹ C1 A1
- d = v/H₀ = 2.6 × 10²⁴ m A1
- Evidence for the Big Bang: all distant galaxies are redshifted, and v ∝ d, so the universe is expanding; running it backwards suggests it began from a very hot, dense state.
- Age estimate: 1/H₀ ≈ 4.3 × 10¹⁷ s ≈ 14 billion years (ignoring changes in the expansion rate).
Test yourself — cover the answers first
Quick check
- Define luminosity.
- What is a standard candle?
- A star's temperature doubles at the same radius. By what factor does L change?
- Does redshift mean a source is approaching or receding?
- State Hubble's law.
Exam-style
- Two stars have the same luminosity; star A appears 9 times brighter than B. Compare their distances.
- Find λ_max for a star at 3500 K.
- Estimate the age of the universe in years if H₀ = 2.3 × 10⁻¹⁸ s⁻¹.
Show answers
- the total power radiated by a star
- an object of known luminosity
- 16
- receding
- recession speed is proportional to distance, v = H₀d
- F ∝ 1/d², so B is 3 times as far as A
- 8.3 × 10⁻⁷ m (red/infrared)
- 1/H₀ = 4.3 × 10¹⁷ s ≈ 1.4 × 10¹⁰ years
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