C.5 Doppler effect
The Doppler effect for sound and light, wavefront diagrams for a moving source, redshift and blueshift of spectral lines as evidence for moving stars and galaxies, and (HL) the moving-source and moving-observer equations for sound.
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In 30 seconds
- The Doppler effect is the change in observed frequency and wavelength when the source and observer move relative to each other.
- Approaching: higher frequency, shorter wavelength. Moving apart: lower frequency, longer wavelength.
- For light (v ≪ c): Δf/f = Δλ/λ ≈ v/c. Spectral lines from receding galaxies are redshifted, the key evidence for the expanding universe.
- HL: for sound, f′ = f v/(v ± us) for a moving source and f′ = f(v ± uo)/v for a moving observer.
By the end you can
- Describe the Doppler effect for sound and EM waves with wavefront diagrams.
- Use Δf/f = Δλ/λ ≈ v/c for light.
- Explain redshift and blueshift as evidence for the motion of stars and galaxies.
- Use the Doppler equations for a moving source and a moving observer of sound. HL
1What the Doppler effect is
- Why: the wave speed through the medium does not change, but a moving source emits each wavefront from a new position, so the wavefronts are closer together ahead of it. A moving observer meets wavefronts more often (or less often).
- Everyday examples: the falling pitch of a passing siren or racing car; police radar; ultrasound measuring blood flow.
2Light: redshift and blueshift
The hydrogen line at 656.3 nm is observed at 662.0 nm in a galaxy's spectrum. Find the galaxy's speed and direction.
- Δλ = 662.0 − 656.3 = 5.7 nm A1
- v = cΔλ/λ = 3.00 × 108 × 5.7/656.3 M1
- = 2.6 × 106 m s−1, moving away (redshift) A1
- Evidence from astronomy: distant galaxies are redshifted, and more distant ones more strongly: the universe is expanding. Binary stars show lines that shift back and forth as the stars orbit each other.
3Sound: the Doppler equations HL
A siren of 500 Hz moves at 30 m s−1 (v = 340 m s−1). Find the frequency heard as it approaches and as it moves away.
- approaching: f′ = 500 × 340/(340 − 30) = 548 Hz M1A1
- receding: f′ = 500 × 340/(340 + 30) = 460 Hz A1
A cyclist rides at 20 m s−1 towards a stationary 500 Hz source. What frequency does she hear?
- f′ = f(v + uo)/v = 500 × 360/340 M1
- = 529 Hz A1
Test yourself — cover the answers first
Quick check
- Does the speed of sound change when the source moves?
- What is redshift?
- Why do spectral lines give strong evidence for galaxy motion?
- A star's line shifts to a shorter wavelength. Is it approaching or receding?
- HL Which gives the bigger frequency change: source or observer moving at the same speed towards each other?
Exam-style
- A star's spectral line at 500.0 nm (lab) is observed at 499.5 nm. Find its speed.
- HL A train horn is heard at 520 Hz as the train approaches and 480 Hz as it leaves (v = 340 m s−1). Find the train's speed.
Show answers
- No: frequency and wavelength change, not the wave speed in the medium.
- an increase in the observed wavelength because the source is moving away
- the same pattern of lines is shifted, so it is the same element moving
- approaching (blueshift)
- the moving source (slightly larger)
- Δλ = −0.5 nm
v = c × 0.5/500
= 3.0 × 105 m s−1 towards us - 520(340 − u) = 480(340 + u)
176 800 − 520u = 163 200 + 480u
u = 13 600/1000 = 13.6 m s−1
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