Polynomials, rational functions and inequalities
Reciprocal and rational functions with their asymptotes, and for HL: the factor and remainder theorems, polynomial graphs, sum and product of roots, oblique asymptotes, and solving polynomial and rational inequalities.
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In 30 seconds
- A rational function y = (ax + b)/(cx + d) has a vertical asymptote where the denominator is zero (x = −d/c) and a horizontal asymptote y = a/c.
- HL factor theorem: (x − a) is a factor of p(x) ⇔ p(a) = 0. Remainder theorem: dividing p(x) by (x − a) leaves remainder p(a).
- HL: for a polynomial anxn + … + a0, the roots add to −an−1/an and multiply to (−1)na0/an.
- HL inequalities: find the critical values (roots, asymptotes), then test the sign between them; a sketch or sign chart beats algebra tricks.
By the end you can
- Sketch y = 1/x and y = (ax + b)/(cx + d), with intercepts and asymptotes.
- Use the factor and remainder theorems to factorise polynomials and find unknowns. HL
- Sketch polynomial graphs from their factors, including repeated roots. HL
- Use the sum and product of roots. HL
- Sketch rational functions with oblique asymptotes. HL
- Solve polynomial and rational inequalities, analytically and graphically. HL
1Reciprocal and rational functions
- y = 1/x is self-inverse, with asymptotes x = 0 and y = 0. y = k/x is a stretch of it.
- For y = ax + bcx + d: vertical asymptote x = −d/c; horizontal asymptote y = a/c; x-intercept where ax + b = 0; y-intercept b/d.
Sketch y = 2x + 1x − 3: give asymptotes and intercepts.
- vertical x = 3, horizontal y = 2 A1A1
- x-intercept (−0.5, 0), y-intercept (0, −⅓) A1
2Polynomials HL
Factorise p(x) = x3 − 4x2 + x + 6 completely.
- p(−1) = −1 − 4 − 1 + 6 = 0, so (x + 1) is a factor M1
- divide: x3 − 4x2 + x + 6 = (x + 1)(x2 − 5x + 6) A1
- = (x + 1)(x − 2)(x − 3) A1
When 2x3 + ax2 − 5 is divided by (x − 2) the remainder is 15. Find a.
- p(2) = 16 + 4a − 5 = 15 M1
- a = 1 A1
Find the sum and product of the roots of 2x3 − 3x2 + 4x − 5 = 0.
- sum = −(−3)/2 = 32 A1
- product = (−1)3(−5)/2 = 52 A1
- Complex roots count too: a polynomial of degree n has exactly n roots (some may be complex, some repeated).
3Rational functions with oblique asymptotes HL
- Degree of top = degree of bottom + 1: divide to find an oblique asymptote. x2 + 3x + 5x + 1 = x + 2 + 3x + 1, so the asymptotes are x = −1 and y = x + 2.
- Degree of top < degree of bottom (e.g. xx2 − 4): horizontal asymptote y = 0, vertical asymptotes at each root of the denominator.
Find all asymptotes of y = 2x2 − x + 1x − 1.
- vertical x = 1 A1
- divide: 2x2 − x + 1 = (x − 1)(2x + 1) + 2 M1
- oblique y = 2x + 1 A1
4Inequalities HL
Solve (x + 2)(x − 1)(x − 4) > 0.
- critical values −2, 1, 4 A1
- sign chart (or sketch of the cubic) M1
- −2 < x < 1 or x > 4 A1
Solve x + 1x − 2 ≤ 2.
- x + 1x − 2 − 2 ≤ 0 ⇒ 5 − xx − 2 ≤ 0 M1
- critical values x = 2 (excluded) and x = 5 A1
- x < 2 or x ≥ 5 A1
Test yourself — cover the answers first
Quick check
- State the asymptotes of y = 3/(x + 1) − 2.
- Find the horizontal asymptote of y = (4x − 1)/(2x + 5).
- HL Is (x − 2) a factor of x3 − 8?
- HL Find the remainder when x3 + 2x − 1 is divided by (x + 1).
- HL What does a double root look like on a graph?
- HL Solve x2(x − 3) ≥ 0.
Exam-style
- HL x = 2 is a root of x3 + kx2 − x − 2 = 0. Find k and the other roots.
- HL Solve 3x − 1 < 2x.
Show answers
- x = −1 and y = −2
- y = 2
- yes: p(2) = 0
- p(−1) = −4
- the curve touches the x-axis and turns back
- x = 0 or x ≥ 3
- 8 + 4k − 2 − 2 = 0 ⇒ k = −1
x3 − x2 − x − 2 = (x − 2)(x2 + x + 1)
other roots x = (−1 ± √3 i)/2 (complex) - 3/(x − 1) − 2/x < 0 ⇒ x + 2x(x − 1) < 0
critical values −2, 0, 1
x < −2 or 0 < x < 1
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